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#include "graph/count/count_C3_C4.hpp"
#include "graph/base.hpp" // 各点に対してその点を含む C3, C4 を数える // simple graph を仮定 template <typename GT> pair<vi, vi> count_C3_C4_pointwise(GT &G) { static_assert(!GT::is_directed); int N = G.N; auto deg = G.deg_array(); auto I = argsort(deg); reverse(all(I)); vc<int> rk(N); FOR(i, N) rk[I[i]] = i; // 遷移先を降順に並べる vvc<int> TO(N); for (auto &&e: G.edges) { int a = rk[e.frm], b = rk[e.to]; TO[a].eb(b), TO[b].eb(a); } FOR(v, N) { sort(all(TO[v])), reverse(all(TO[v])); } vc<int> A(N); vi C3(N), C4(N); FOR(a, N) { for (auto &b: TO[a]) TO[b].pop_back(); for (auto &b: TO[a]) { for (auto &c: TO[b]) { C4[a] += A[c], C4[c] += A[c], A[c] += 1; } } for (auto &b: TO[a]) { C3[a] += A[b], C3[b] += A[b] + A[b]; for (auto &c: TO[b]) { C4[b] += A[c] - 1; } } for (auto &b: TO[a]) { for (auto &c: TO[b]) { A[c] = 0; } } } for (auto &x: C3) x /= 2; C3 = rearrange(C3, rk), C4 = rearrange(C4, rk); return {C3, C4}; } // (2e5,5e5) で 500 ms // https://codeforces.com/gym/104053/problem/K template <typename GT> pair<ll, ll> count_C3_C4(GT &G) { static_assert(!GT::is_directed); int N = G.N; ll x3 = 0, x4 = 0; auto deg = G.deg_array(); auto I = argsort(deg); reverse(all(I)); vc<int> rk(N); FOR(i, N) rk[I[i]] = i; // 遷移先を降順に並べる vvc<int> TO(N); for (auto &&e: G.edges) { int a = rk[e.frm], b = rk[e.to]; if (a != b) TO[a].eb(b), TO[b].eb(a); } FOR(v, N) { sort(all(TO[v])); reverse(all(TO[v])); } vc<int> A(N); FOR(a, N) { for (auto &&b: TO[a]) TO[b].pop_back(); for (auto &&b: TO[a]) { for (auto &&c: TO[b]) { x4 += A[c]++; } } for (auto &&b: TO[a]) { x3 += A[b]; } for (auto &&b: TO[a]) { for (auto &&c: TO[b]) { A[c] = 0; } } } x3 /= 2; return {x3, x4}; }
#line 2 "graph/base.hpp" template <typename T> struct Edge { int frm, to; T cost; int id; }; template <typename T = int, bool directed = false> struct Graph { static constexpr bool is_directed = directed; int N, M; using cost_type = T; using edge_type = Edge<T>; vector<edge_type> edges; vector<int> indptr; vector<edge_type> csr_edges; vc<int> vc_deg, vc_indeg, vc_outdeg; bool prepared; class OutgoingEdges { public: OutgoingEdges(const Graph* G, int l, int r) : G(G), l(l), r(r) {} const edge_type* begin() const { if (l == r) { return 0; } return &G->csr_edges[l]; } const edge_type* end() const { if (l == r) { return 0; } return &G->csr_edges[r]; } private: const Graph* G; int l, r; }; bool is_prepared() { return prepared; } Graph() : N(0), M(0), prepared(0) {} Graph(int N) : N(N), M(0), prepared(0) {} void build(int n) { N = n, M = 0; prepared = 0; edges.clear(); indptr.clear(); csr_edges.clear(); vc_deg.clear(); vc_indeg.clear(); vc_outdeg.clear(); } void add(int frm, int to, T cost = 1, int i = -1) { assert(!prepared); assert(0 <= frm && 0 <= to && to < N); if (i == -1) i = M; auto e = edge_type({frm, to, cost, i}); edges.eb(e); ++M; } #ifdef FASTIO // wt, off void read_tree(bool wt = false, int off = 1) { read_graph(N - 1, wt, off); } void read_graph(int M, bool wt = false, int off = 1) { for (int m = 0; m < M; ++m) { INT(a, b); a -= off, b -= off; if (!wt) { add(a, b); } else { T c; read(c); add(a, b, c); } } build(); } #endif void build() { assert(!prepared); prepared = true; indptr.assign(N + 1, 0); for (auto&& e: edges) { indptr[e.frm + 1]++; if (!directed) indptr[e.to + 1]++; } for (int v = 0; v < N; ++v) { indptr[v + 1] += indptr[v]; } auto counter = indptr; csr_edges.resize(indptr.back() + 1); for (auto&& e: edges) { csr_edges[counter[e.frm]++] = e; if (!directed) csr_edges[counter[e.to]++] = edge_type({e.to, e.frm, e.cost, e.id}); } } OutgoingEdges operator[](int v) const { assert(prepared); return {this, indptr[v], indptr[v + 1]}; } vc<int> deg_array() { if (vc_deg.empty()) calc_deg(); return vc_deg; } pair<vc<int>, vc<int>> deg_array_inout() { if (vc_indeg.empty()) calc_deg_inout(); return {vc_indeg, vc_outdeg}; } int deg(int v) { if (vc_deg.empty()) calc_deg(); return vc_deg[v]; } int in_deg(int v) { if (vc_indeg.empty()) calc_deg_inout(); return vc_indeg[v]; } int out_deg(int v) { if (vc_outdeg.empty()) calc_deg_inout(); return vc_outdeg[v]; } #ifdef FASTIO void debug() { print("Graph"); if (!prepared) { print("frm to cost id"); for (auto&& e: edges) print(e.frm, e.to, e.cost, e.id); } else { print("indptr", indptr); print("frm to cost id"); FOR(v, N) for (auto&& e: (*this)[v]) print(e.frm, e.to, e.cost, e.id); } } #endif vc<int> new_idx; vc<bool> used_e; // G における頂点 V[i] が、新しいグラフで i になるようにする // {G, es} // sum(deg(v)) の計算量になっていて、 // 新しいグラフの n+m より大きい可能性があるので注意 Graph<T, directed> rearrange(vc<int> V, bool keep_eid = 0) { if (len(new_idx) != N) new_idx.assign(N, -1); int n = len(V); FOR(i, n) new_idx[V[i]] = i; Graph<T, directed> G(n); vc<int> history; FOR(i, n) { for (auto&& e: (*this)[V[i]]) { if (len(used_e) <= e.id) used_e.resize(e.id + 1); if (used_e[e.id]) continue; int a = e.frm, b = e.to; if (new_idx[a] != -1 && new_idx[b] != -1) { history.eb(e.id); used_e[e.id] = 1; int eid = (keep_eid ? e.id : -1); G.add(new_idx[a], new_idx[b], e.cost, eid); } } } FOR(i, n) new_idx[V[i]] = -1; for (auto&& eid: history) used_e[eid] = 0; G.build(); return G; } Graph<T, true> to_directed_tree(int root = -1) { if (root == -1) root = 0; assert(!is_directed && prepared && M == N - 1); Graph<T, true> G1(N); vc<int> par(N, -1); auto dfs = [&](auto& dfs, int v) -> void { for (auto& e: (*this)[v]) { if (e.to == par[v]) continue; par[e.to] = v, dfs(dfs, e.to); } }; dfs(dfs, root); for (auto& e: edges) { int a = e.frm, b = e.to; if (par[a] == b) swap(a, b); assert(par[b] == a); G1.add(a, b, e.cost); } G1.build(); return G1; } private: void calc_deg() { assert(vc_deg.empty()); vc_deg.resize(N); for (auto&& e: edges) vc_deg[e.frm]++, vc_deg[e.to]++; } void calc_deg_inout() { assert(vc_indeg.empty()); vc_indeg.resize(N); vc_outdeg.resize(N); for (auto&& e: edges) { vc_indeg[e.to]++, vc_outdeg[e.frm]++; } } }; #line 2 "graph/count/count_C3_C4.hpp" // 各点に対してその点を含む C3, C4 を数える // simple graph を仮定 template <typename GT> pair<vi, vi> count_C3_C4_pointwise(GT &G) { static_assert(!GT::is_directed); int N = G.N; auto deg = G.deg_array(); auto I = argsort(deg); reverse(all(I)); vc<int> rk(N); FOR(i, N) rk[I[i]] = i; // 遷移先を降順に並べる vvc<int> TO(N); for (auto &&e: G.edges) { int a = rk[e.frm], b = rk[e.to]; TO[a].eb(b), TO[b].eb(a); } FOR(v, N) { sort(all(TO[v])), reverse(all(TO[v])); } vc<int> A(N); vi C3(N), C4(N); FOR(a, N) { for (auto &b: TO[a]) TO[b].pop_back(); for (auto &b: TO[a]) { for (auto &c: TO[b]) { C4[a] += A[c], C4[c] += A[c], A[c] += 1; } } for (auto &b: TO[a]) { C3[a] += A[b], C3[b] += A[b] + A[b]; for (auto &c: TO[b]) { C4[b] += A[c] - 1; } } for (auto &b: TO[a]) { for (auto &c: TO[b]) { A[c] = 0; } } } for (auto &x: C3) x /= 2; C3 = rearrange(C3, rk), C4 = rearrange(C4, rk); return {C3, C4}; } // (2e5,5e5) で 500 ms // https://codeforces.com/gym/104053/problem/K template <typename GT> pair<ll, ll> count_C3_C4(GT &G) { static_assert(!GT::is_directed); int N = G.N; ll x3 = 0, x4 = 0; auto deg = G.deg_array(); auto I = argsort(deg); reverse(all(I)); vc<int> rk(N); FOR(i, N) rk[I[i]] = i; // 遷移先を降順に並べる vvc<int> TO(N); for (auto &&e: G.edges) { int a = rk[e.frm], b = rk[e.to]; if (a != b) TO[a].eb(b), TO[b].eb(a); } FOR(v, N) { sort(all(TO[v])); reverse(all(TO[v])); } vc<int> A(N); FOR(a, N) { for (auto &&b: TO[a]) TO[b].pop_back(); for (auto &&b: TO[a]) { for (auto &&c: TO[b]) { x4 += A[c]++; } } for (auto &&b: TO[a]) { x3 += A[b]; } for (auto &&b: TO[a]) { for (auto &&c: TO[b]) { A[c] = 0; } } } x3 /= 2; return {x3, x4}; }