This documentation is automatically generated by online-judge-tools/verification-helper
#include "graph/count/count_C3_C4.hpp"
// 各点に対して、その点を含む C3, C4 を数える
template <typename GT>
pair<vi, vi> count_C3_C4_pointwise(GT &G) {
int N = G.N;
auto deg = G.deg_array();
auto I = argsort(deg);
reverse(all(I));
vc<int> rk(N);
FOR(i, N) rk[I[i]] = i;
// 遷移先を降順に並べる
vvc<int> TO(N);
for (auto &&e: G.edges) {
int a = rk[e.frm], b = rk[e.to];
TO[a].eb(b);
TO[b].eb(a);
}
FOR(v, N) {
sort(all(TO[v]));
reverse(all(TO[v]));
}
vc<int> A(N);
vi C3(N), C4(N);
FOR(a, N) {
for (auto &&b: TO[a]) TO[b].pop_back();
for (auto &&b: TO[a]) {
for (auto &&c: TO[b]) { C4[a] += A[c], C4[c] += A[c], A[c] += 1; }
}
for (auto &&b: TO[a]) {
C3[a] += A[b], C3[b] += A[b] + A[b];
for (auto &&c: TO[b]) { C4[b] += A[c] - 1; }
}
for (auto &&b: TO[a]) {
for (auto &&c: TO[b]) { A[c] = 0; }
}
}
for (auto &&x: C3) x /= 2;
C3 = rearrange(C3, rk);
C4 = rearrange(C4, rk);
return {C3, C4};
}
// (2e5,5e5) で 500 ms
// https://codeforces.com/gym/104053/problem/K
template <typename GT>
pair<ll, ll> count_C3_C4(GT &G) {
int N = G.N;
ll x3 = 0, x4 = 0;
auto deg = G.deg_array();
auto I = argsort(deg);
reverse(all(I));
vc<int> rk(N);
FOR(i, N) rk[I[i]] = i;
// 遷移先を降順に並べる
vvc<int> TO(N);
for (auto &&e: G.edges) {
int a = rk[e.frm], b = rk[e.to];
TO[a].eb(b);
TO[b].eb(a);
}
FOR(v, N) {
sort(all(TO[v]));
reverse(all(TO[v]));
}
vc<int> A(N);
FOR(a, N) {
for (auto &&b: TO[a]) TO[b].pop_back();
for (auto &&b: TO[a]) {
for (auto &&c: TO[b]) { x4 += A[c]++; }
}
for (auto &&b: TO[a]) { x3 += A[b]; }
for (auto &&b: TO[a]) {
for (auto &&c: TO[b]) { A[c] = 0; }
}
}
x3 /= 2;
return {x3, x4};
}
#line 1 "graph/count/count_C3_C4.hpp"
// 各点に対して、その点を含む C3, C4 を数える
template <typename GT>
pair<vi, vi> count_C3_C4_pointwise(GT &G) {
int N = G.N;
auto deg = G.deg_array();
auto I = argsort(deg);
reverse(all(I));
vc<int> rk(N);
FOR(i, N) rk[I[i]] = i;
// 遷移先を降順に並べる
vvc<int> TO(N);
for (auto &&e: G.edges) {
int a = rk[e.frm], b = rk[e.to];
TO[a].eb(b);
TO[b].eb(a);
}
FOR(v, N) {
sort(all(TO[v]));
reverse(all(TO[v]));
}
vc<int> A(N);
vi C3(N), C4(N);
FOR(a, N) {
for (auto &&b: TO[a]) TO[b].pop_back();
for (auto &&b: TO[a]) {
for (auto &&c: TO[b]) { C4[a] += A[c], C4[c] += A[c], A[c] += 1; }
}
for (auto &&b: TO[a]) {
C3[a] += A[b], C3[b] += A[b] + A[b];
for (auto &&c: TO[b]) { C4[b] += A[c] - 1; }
}
for (auto &&b: TO[a]) {
for (auto &&c: TO[b]) { A[c] = 0; }
}
}
for (auto &&x: C3) x /= 2;
C3 = rearrange(C3, rk);
C4 = rearrange(C4, rk);
return {C3, C4};
}
// (2e5,5e5) で 500 ms
// https://codeforces.com/gym/104053/problem/K
template <typename GT>
pair<ll, ll> count_C3_C4(GT &G) {
int N = G.N;
ll x3 = 0, x4 = 0;
auto deg = G.deg_array();
auto I = argsort(deg);
reverse(all(I));
vc<int> rk(N);
FOR(i, N) rk[I[i]] = i;
// 遷移先を降順に並べる
vvc<int> TO(N);
for (auto &&e: G.edges) {
int a = rk[e.frm], b = rk[e.to];
TO[a].eb(b);
TO[b].eb(a);
}
FOR(v, N) {
sort(all(TO[v]));
reverse(all(TO[v]));
}
vc<int> A(N);
FOR(a, N) {
for (auto &&b: TO[a]) TO[b].pop_back();
for (auto &&b: TO[a]) {
for (auto &&c: TO[b]) { x4 += A[c]++; }
}
for (auto &&b: TO[a]) { x3 += A[b]; }
for (auto &&b: TO[a]) {
for (auto &&c: TO[b]) { A[c] = 0; }
}
}
x3 /= 2;
return {x3, x4};
}